8(1[y+2]1)=40

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Solution for 8(1[y+2]1)=40 equation:


Simplifying
8(1[y + 2] * 1) = 40

Reorder the terms:
8(1[2 + y] * 1) = 40

Reorder the terms for easier multiplication:
8(1 * 1[2 + y]) = 40

Multiply 1 * 1
8(1[2 + y]) = 40
8([2 * 1 + y * 1]) = 40
8([2 + 1y]) = 40
(2 * 8 + 1y * 8) = 40
(16 + 8y) = 40

Solving
16 + 8y = 40

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 8y = 40 + -16

Combine like terms: 16 + -16 = 0
0 + 8y = 40 + -16
8y = 40 + -16

Combine like terms: 40 + -16 = 24
8y = 24

Divide each side by '8'.
y = 3

Simplifying
y = 3

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